Problem
Prove that 1/1999<\ln (1999/1998 )<1/1998
Solution
Since 1999/1998=1+1/1998, by the power series expansion of \ln(1+x) we have that \ln(1999/1998)<1/1998. Also, since \ln(1999/1998)=-\ln(1998/1999)=-\ln(1-1/1999) and \ln(1-1/1999)<-1/1999, we have that 1/1999<\ln(1999/1998).
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